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24x^2=150
We move all terms to the left:
24x^2-(150)=0
a = 24; b = 0; c = -150;
Δ = b2-4ac
Δ = 02-4·24·(-150)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*24}=\frac{-120}{48} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*24}=\frac{120}{48} =2+1/2 $
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